(p^2)-(2p)+6=2

Solution for (p^2)-(2p)+6=2 equation:

Simplifying
(p2) + -1(2p) + 6 = 2
p2 + -1(2p) + 6 = 2

Remove parenthesis around (2p)
p2 + -1 * 2p + 6 = 2

Multiply -1 * 2
p2 + -2p + 6 = 2

Reorder the terms:
6 + -2p + p2 = 2

Solving
6 + -2p + p2 = 2

Solving for variable 'p'.

Reorder the terms:
6 + -2 + -2p + p2 = 2 + -2

Combine like terms: 6 + -2 = 4
4 + -2p + p2 = 2 + -2

Combine like terms: 2 + -2 = 0
4 + -2p + p2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + -2p + -4 + p2 = 0 + -4

Reorder the terms:
4 + -4 + -2p + p2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -2p + p2 = 0 + -4
-2p + p2 = 0 + -4

Combine like terms: 0 + -4 = -4
-2p + p2 = -4

The p term is -2p.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2p + 1 + p2 = -4 + 1

Reorder the terms:
1 + -2p + p2 = -4 + 1

Combine like terms: -4 + 1 = -3
1 + -2p + p2 = -3

Factor a perfect square on the left side:
(p + -1)(p + -1) = -3

Can't calculate square root of the right side.

The solution to this equation could not be determined.